The Toronto Blue Jays look like the superteam that was promised so far in the early 2022 MLB season. They have a 12-6 record, the fourth-best in Major League Baseball at the moment, and several of their stars are shining bright. Although Vladimir Guerrero Jr. is still mashing and Alek Manoah has been unbeatable, Kevin Gausman is having a historically dominant start to the season.
The Blue Jays' pitching rotation has been very good and Gausman has been the best one. The 31-year-old has been nothing short of amazing so far. He has recorded an ERA of 2.19 through four starts and 24.2 innings. He also has an outrageous FIP of 0.56 and has not allowed a single home run or walk yet.
In what appears to be an unbelievable record, Kevin Gausman has broken the record for most strikeouts before allowing a walk during the first season with a new team since 1900. Of all the legends to pitch over the previous 120+ years, the Blue Jays' new star is a cut above the rest.
Through last night's start, Kevin Gausman has 31 strikeouts and 0 walks to begin his tenure with the Blue Jays.
Per @EliasSports, that's the longest streak of strikeouts without a walk by any starting pitcher to begin a stint with a team in modern MLB history (since 1900). pic.twitter.com/p7noY6Fl4E
— ESPN Stats & Info (@ESPNStatsInfo) April 27, 2022
Superstars like Nolan Ryan, Pedro Martinez, Greg Maddux, Randy Johnson and Max Scherzer, just to name a few, have changed teams several times throughout their careers.
Gausman's 31 strikeouts tie him with Shane McClanahan 0f the Tampa Bay Rays for the most in the American League and the fourth most in all of MLB. After receiving Cy Young Award votes and leaving the San Francisco Giants, he is tearing batters apart. Thanks to his nasty splitter, he racks up whiffs at a phenomenal rate and prevents extra-base hits.
The trade-off Gausman made is allowing higher contact, as he has allowed a staggering 25 hits so far, which only five other pitchers have done. However, as long as he keeps rocking a strikeout-per-walk ratio of infinity (or, at least, somewhere close) it won't matter.
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