The Baltimore Ravens are signing defensive lineman Derek Wolfe to a one-year deal worth up to $6 million.
Former Broncos’ DE Derek Wolfe reached agreement on an 1-year deal worth up to $6 million with the Baltimore Ravens, per source.
— Adam Schefter (@AdamSchefter) March 28, 2020
Wolfe spent the first eight years of his NFL career with the Denver Broncos. He is coming off of a 2019 campaign in which he was limited to 12 games due to an elbow injury. During the time he was on the field, Wolfe was pretty productive, registering 34 tackles, seven sacks and a forced fumble.
The 30-year-old was originally selected by the Broncos in the second round (36th pick overall) of the 2012 NFL Draft.
He started every contest in his rookie year, finishing with 40 tackles and six sacks. The following season, Wolfe took a step back, as he missed five games due to injuries and logged just 16 tackles and four sacks.
After a quiet 2014 campaign, Wolfe bounced back with a strong 2015, totaling 49 tackles and 5.5 sacks in 12 contests. He was also a part of a dominant Denver defense that led the way to a Super Bowl title.
Wolfe had another solid season in 2016, recording 51 tackles and 5.5 sacks.
The Lisbon, Oh. native then accumulated a grand total of 3.5 sacks between 2017 and 2018. He enjoyed one of the best years of his career this past season.
While Wolfe is not elite in any one particular area, he is a very solid all-around defensive lineman. He should be of help to a Ravens defense that is already stingy as it is.
Baltimore finished with the best record in the NFL this past year, going 14-2. However, the Ravens did not win a playoff game, falling to the Tennessee Titans in the Divisional Round.
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