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The Detroit Pistons traded for former L.A. Clippers star Blake Griffin last week. The move hopefully put them in the conversation for a playoff spot in the Eastern Conference, especially seeing as how good Griffin is.
With Griffin and Andre Drummond, there is a definite one-two punch dynamic on the Pistons. And with Reggie Jackson being injured but still on the team, head coach Stan Van Gundy believes he has his own version of a Big Three, per Rod Beard of the Detroit News.
#Pistons SVG on trading for another significant piece, to create a "Big Three": "To me, the third piece is Reggie (Jackson). That’s pretty good. That’s a pretty good three. We’ve got it in place; we just don’t have it on the court right now."
— Rod Beard (@detnewsRodBeard) February 5, 2018
The term “Big Three” has usually been saved for three stars brought together to play on the same team. Some of the famous NBA threesomes were Paul Pierce, Ray Allen and Kevin Garnett in Boston, and LeBron James, Dwyane Wade and Chris Bosh in Miami.
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With the three players in Detroit that Van Gundy is speaking of, Griffin is arguably the only player that fits the caliber of any of the previous six mentioned. Drummond and Jackson are good players in their own rights, but it'd be difficult to call them stars.
Furthermore, none of those players have had their own teams in their careers. Jackson has played with Drummond for the entire time he's been on the Pistons. And Griffin has played with DeAndre Jordan for his entire career.
However, it can be argued that the Clippers were Griffin's team before Chris Paul joined.
Either way, the “Big Three” moniker may be a bit premature. But one thing is for sure. If those three players find a way to maximize each other's potentials, there is no reason that they can't become the Big Three in Detroit.
But that will take time.
