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LeBron James passes Kobe Bryant for third most triple-doubles in Lakers history


LeBron James made history yet again for the Los Angeles Lakers on Tuesday in Game 1 of LA’s first-round matchup against the Portland Trail Blazers. With LeBron logging a triple-double late in the third quarter, he just passed the late, great Kobe Bryant for the third most triple-doubles in Lakers franchise history.

This is yet another milestone for LeBron, and the fact that he passes Kobe in this particular category also provides a sentimental ring to this personal accolade.

What’s amazing here is that this is just LeBron’s second season with the Lakers. He’s already put up 22 triple-doubles, as opposed to Kobe’s 21 which he achieved in 18 seasons with the Lakers. This simply speaks volumes of the type of all-around play James delivers on a nightly basis.

The Lakers come into this matchup as the heavy favorites against the eighth-seeded Blazers. However, there’s no denying that Portland has the momentum going for them, following what was an amazing run for them during the seeding games. Damian Lillard, who has been scorching hot since the restart, was awarded the bubble MVP award for his awe-inspiring exploits during the seeding games. If there’s anyone who will carry this team to an upset against the Lakers, it has got to be him.

On the contrary, the Lakers have struggled since the restart. Despite clinching the first seed in the conference, they were only able to win three out of eight seeding games, and entered the playoffs with perhaps more questions than answers. Then again, everything changes for LeBron once he enters playoffs mode, and surely, his teammates should follow suit.