It's official. After months and months of discussion, the Seattle Seahawks and star safety Jamal Adams have reached an agreement on a new contract, making him the highest-paid safety in the league. According to Ian Rapoport of NFL Network, the deal is for four years and worth $70 million, a huge step in the right direction for the Seahawks.
The #Seahawks have agreed to terms on a large extension for star S Jamal Adams, a 4-year, $70M deal that makes him the league’s highest paid safety, I’m told. He gets $38M guaranteed, breaking the stalemate. A long time coming and well-deserved. 💰💰💰
— Ian Rapoport (@RapSheet) August 17, 2021
It was never a matter of if a deal was going to be done, but when. The two sides tried and tried and tried again, and now finally it is done and Adams is getting a ton of money after the Seahawks traded for him from the New York Jets.
The safety was sitting out of practice while waiting for a deal to be done, and Seattle wanted nothing more than for him to return to the field as they aim to make some noise in the NFC West.
Jamal Adams has sat out practice while the deal was negotiated. His participation is now imminent, which is a win for the #Seahawks and Adams. They get him back on the field with time to prepare for the season. https://t.co/bnZiKTDVtJ
— Ian Rapoport (@RapSheet) August 17, 2021
Adams is one of the best safeties in the NFL and the Seahawks didn't want to take any chance of him hitting the free agency market. Now, they won't have to, and Russell Wilson and Pete Carroll have to be jumping for joy after hearing the news.
The former LSU Tiger went sixth overall in the 2017 NFL Draft and just wanted the money he deserves. In 2020, his first with Seattle, he had 9.5 sacks, a career-high.
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