The Milwaukee Bucks will be shaking things up on their roster as they are reportedly going to make a few moves. DeAndre Liggins has been informed that he will be waived by the team, which will result in having a roster spot open. That said, the Bucks are planning to sign Wisconsin Herd standout Xavier Munford to a two-way contract, according to Shams Charania of The Vertical.

Parting ways with Liggins will bring the team to around $5.1 million below the luxury tax line and they are expected to shuffle their two-way contract players for the remainder of the season. However, Munford’s potential signing will mean they will have to let go of either Sean Kilpatrick orJoel Bolomboy, as the NBA only allows a maximum of two players with that kind of contract on a team.

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The Rhode Island product went undrafted back in 2014 before he decided to take his talents to the G League. Xavier Munford played for the Bakersfield Jam for three years and received a call-up from the Memphis Grizzlies in 2016, appearing in 14 games for them and averaging 5.7 points, 2.2 rebounds, and 1.6 assists in 17.4 minutes per game.

Munford also has international basketball experience being part of the U.S. Men's Basketball Team in last summer’s FIBA AmeriCup tournament, helping the country secure the gold medal.

Now that he will get the opportunity to play in the NBA again, it can be expected that he will only receive limited playing time as the Bucks already have Eric Bledsoe, Malcolm Brogdon, and Mathew Dellavedova in their point guard rotation. However, Xavier Munford can also play at the shooting guard spot especially with his ability to knock down 3-pointers.